![]() However, that is is reasonable when we say that L1 is accessed sometimes. I agree with this one! You can see further details here.Ģ- As discussed here, we can calculate that using Teff = h1*t1 + (1-h1)*h2*t2 + (1-h1)*(1-h2)*t3 which yields 24. Then with the miss rate of L1, we access lower levels and that is repeated recursively. The logic behind that is to access L1, first. T1 means the time to access the L1 while t2 and t3 mean the penalty to access L2 and main memory, respectively.ġ- Teff = t1 + (1-h1) which will be 32. All are reasonable, but I don't know how they differ and what is the correct one.Īssume a two-level cache and a main memory system with the following specs: h1 = 80% t1 = 10ns L1 cache In order to calculate the effective access time of a memory sub-system, I see some different approaches, a.k.a formulas.
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